type 8 alligation & mixtures based ratio & proportion problems Practice Questions Answers Test with Solutions & More Shortcuts
ratio & proportion PRACTICE TEST [9 - EXERCISES]
type 1 basic concepts of ratio & proportion
type 2 age based ratio & proportion problems
type 3 addition subtraction product on ratio & proportion
type 4 income & expenditure based ratio & proportion problems
type 5 shares & partnership based ratio & proportion problems
type 6 fractions based ratio & proportion problems
type 7 finding sum difference product based ratio & proportion problems
type 8 alligation & mixtures based ratio & proportion problems
type 9 coins & rupees based ratio & proportion problems
Question : 1 [SSC MTS 2013]
The ratio in which a man must mix rice at Rs.10.20 per kg and Rs.14.40 per kg so as to make a mixture worth Rs.12.60 per kg, is
a) 18 : 24
b) 3 : 4
c) 2 : 5
d) 4 : 3
Answer »Answer: (b)
Required ratio = 1.8 : 2.4
= 18 : 24 = 3 : 4
Question : 2 [SSC CPO S.I.2007]
The milk and water in a mixture are in the ratio 7 : 5. When 15 litres of water are added to it, the ratio of milk and water in the new mixture becomes 7 : 8. The total quantity of water in the new mixture is
a) 60 litres
b) 96 litres
c) 40 litres
d) 35 litres
Answer »Answer: (c)
Let the quantity of milk in the mixture = 7x litres and that of water = 5x litres.
According to the question,
${7x}/{5x + 15} = 7/8$
56x = 35x + 105
56 x - 35 x = 105
21x = 105
$x = 105/21$ =5
Required quantity of water
= (5x + 15) litres
= 5 × 5 + 15 = 40 litres
Question : 3 [SSC CGL Prelim 2002]
Zinc and copper are in the ratio of 5 : 3 in 200 gm of an alloy. How much grams of copper be added to make the ratio as 3 : 5?
a) 72
b) 66
c) $1/200$
d) 133$1/3$
Answer »Answer: (d)
Weight of zinc
= $200 × 5/8$= 125 gram
Weight of copper
= $200 × 3/8$ = 75 gram.
Let the ratio of 125 gram zinc and x gram copper be 3 : 5
= $125/x = 3/5$
$x = {125× 5}/3 = 625/3$ gram
Addition of copper in mixture
= $625/3 - 75 = {625 - 225}/3$
= $400/3 = 133{1}/3$ gram.
Question : 4 [SSC CPO S.I.2003]
A mixture of 30 litres contain milk and water in the ratio of 7 : 3. How much water should be added to it so that the ratio of milk and water becomes 3 : 7 ?
a) 56 litres
b) 63 litres
c) 49 litres
d) 40 litres
Answer »Answer: (d)
Quantity of milk in 30 litre mixture
= $30/10 × 7$ = 21litres
Quantity of water
= $30/10 × 3 =9$ litres
Suppose x litres more water is added.
According to question,
$21/{9 + x} = 3/7$
9 + x = 49
x = 40 litres
Question : 5 [SSC CGL Prelim 2002]
In 30 litres mixture of acid, the ratio of acid and water is 2 : 3 . What amount of water should be added to the mixture so that the ratio of acid and water becomes 2 : 5 ?
a) 18 litres
b) 12 litres
c) 15 litres
d) 10 litres
Answer »Answer: (b)
In 30 litres of mixture,
Acid = $2/5 × 30$ = 12 litres
Water = $3/5 × 100$ = 18 litres
$12/{18 + x} = 2/5$
60 = 36 + 2x
2x = 60 - 36 = 24
x = 12 litres of water.
IMPORTANT quantitative aptitude EXERCISES
-
199+ Ratio Proportion Basic Concepts MCQ Questions Answers »
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Top 199+ Ratio Proportion Age Based MCQ Questions Answers »
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159+ Ratios Proportions Addition Subtraction product MCQ »
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199+ Ratio Proportion Income, Expenditure Problems MCQS »
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199+ Partnership Aptitude (Ratio) MCQ Questions Answers »
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259+ Ratio and Proportion (fractions) Aptitude MCQ Quiz »
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199+ Ratio and Proportion Aptitude Questions Answers MCQ »
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299+ Alligation and Mixture Problems Aptitude MCQ Quiz »
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249+ Ratio and Proportion Coins Based Questions Answers »
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